Matrices & Determinants56 questions

Matrices & Determinants — JEE Maths Practice Questions & Solutions

56 questions on Matrices & Determinants with full step-by-step solutions, including past-year (PYQ) problems. Free to practice.

hard
If f(x)=x5sinx2x4tan3x1sec2xsin3xx45f(x) = \begin{vmatrix} x^5 & |\sin x| & 2x^4 \\ \tan^3 x & 1 & \sec 2x \\ \sin^3 x & x^4 & 5 \end{vmatrix}, then π/2π/2f(x)dx\displaystyle\int_{-\pi/2}^{\pi/2} f(x)\,dx is equal to:
View solution →
hard
If Un=1kk2nk2+k+1k2+k2n1k2k2+k+1U_n = \begin{vmatrix} 1 & k & k \\ 2n & k^2+k+1 & k^2+k \\ 2n-1 & k^2 & k^2+k+1 \end{vmatrix} and n=1kUn=110\displaystyle\sum_{n=1}^k U_n = 110, then kk equals:
View solution →
hard
The value of the determinant
2tanAcotB+cotAtanBtanAcotC+cotAtanCtanBcotA+cotBtanA2tanBcotC+cotBtanCtanCcotA+cotCtanAtanCcotB+cotCtanB2\begin{vmatrix} 2 & \tan A\cot B + \cot A\tan B & \tan A\cot C + \cot A\tan C \\ \tan B\cot A + \cot B\tan A & 2 & \tan B\cot C + \cot B\tan C \\ \tan C\cot A + \cot C\tan A & \tan C\cot B + \cot C\tan B & 2 \end{vmatrix}
is:
View solution →
hard
If f(x)=4x4(x2)2x38x42(x22)2(x+1)312x43(x23)2(x1)3f(x) = \begin{vmatrix} 4x-4 & (x-2)^2 & x^3 \\ 8x-4\sqrt{2} & (x-2\sqrt{2})^2 & (x+1)^3 \\ 12x-4\sqrt{3} & (x-2\sqrt{3})^2 & (x-1)^3 \end{vmatrix}, then the coefficient of xx in f(x)f(x) is:
View solution →
hard
Let Δ=a11a12a13a21a22a23a31a32a33\Delta = \begin{vmatrix} a_{11} & a_{12} & a_{13} \\ a_{21} & a_{22} & a_{23} \\ a_{31} & a_{32} & a_{33} \end{vmatrix} where apq=(ip)qa_{pq} = (i^p)^q and i=1i = \sqrt{-1}. The value of Δ\Delta is:
View solution →
hard
If pqr0pqr \neq 0 and the system of equations (p+a)x+by+cz=0(p+a)x+by+cz=0, ax+(q+b)y+cz=0ax+(q+b)y+cz=0, ax+by+(r+c)z=0ax+by+(r+c)z=0 has a non-trivial solution, then ap+bq+cr\dfrac{a}{p}+\dfrac{b}{q}+\dfrac{c}{r} equals:
View solution →
hard
Let S={(a,b)  |  A3=A, where A=(1212ab)}S = \left\{(a, b)\;\middle|\; A^3 = A,\ \text{where}\ A = \begin{pmatrix} \frac{1}{2} & \frac{1}{2} \\ a & b \end{pmatrix}\right\}. Then n(S)n(S) is:
View solution →
hard
Let DkD_k be the k×kk\times k matrix with zeros on the main diagonal, unity as the element of the 1st row and (f(k))th(f(k))^{\text{th}} column, and kk for all other off-diagonal entries. If f(x)=x{x}f(x) = x - \{x\} where {x}\{x\} denotes the fractional part function, then the value of det(D2)+det(D3)\det(D_2) + \det(D_3) equals:
View solution →
hard
Let A=(mnpqr111)A = \begin{pmatrix}\ell & m & n\\ p & q & r\\ 1 & 1 & 1\end{pmatrix} and B=A2B = A^2. If (m)2+(pq)2=9(\ell-m)^2+(p-q)^2 = 9, (mn)2+(qr)2=16(m-n)^2+(q-r)^2 = 16, (n)2+(rp)2=25(n-\ell)^2+(r-p)^2 = 25, then the value of det(B)\det(B) equals:
View solution →
hard
If f(x)=x24x+62x2+4x+103x22x+16x22x+23x1123f(x) = \begin{vmatrix} x^2-4x+6 & 2x^2+4x+10 & 3x^2-2x+16 \\ x-2 & 2x+2 & 3x-1 \\ 1 & 2 & 3 \end{vmatrix}, then f(x)f(x) is:
View solution →
hard
If Δ2=y5z6(z3y3)x4z6(x3z3)y4z5(y3z3)y5z3(y6z6)xz3(z6x6)xy2(x6y6)y5z3(z3y3)xz3(x3z3)xy2(y3x3)\Delta_2 = \begin{vmatrix} y^5z^6(z^3-y^3) & x^4z^6(x^3-z^3) & y^4z^5(y^3-z^3) \\ y^5z^3(y^6-z^6) & xz^3(z^6-x^6) & xy^2(x^6-y^6) \\ y^5z^3(z^3-y^3) & xz^3(x^3-z^3) & xy^2(y^3-x^3) \end{vmatrix} and Δ1=xyz3x4y5z6x7y8z9\Delta_1 = \begin{vmatrix} x & y & z^3 \\ x^4 & y^5 & z^6 \\ x^7 & y^8 & z^9 \end{vmatrix}, then Δ1Δ2\Delta_1\Delta_2 equals:
View solution →
hard
If Δr=2r1x2n123r1y3n145r1z5n1\Delta_r = \begin{vmatrix} 2^{r-1} & x & 2^n-1 \\ 2\cdot3^{r-1} & y & 3^n-1 \\ 4\cdot5^{r-1} & z & 5^n-1 \end{vmatrix}, then r=1nΔr\displaystyle\sum_{r=1}^n \Delta_r is equal to:
View solution →
hard
If x,y,zx, y, z are positive integers and
x3+1x2yx2zxy2y3+1y2zxz2yz2z3+1=30\begin{vmatrix} x^3+1 & x^2y & x^2z \\ xy^2 & y^3+1 & y^2z \\ xz^2 & yz^2 & z^3+1 \end{vmatrix} = 30
then the sum of all possible values of xx is:
View solution →
hard
The determinant 0(ab)2(ac)2(ba)20(bc)2(ca)2(cb)20\begin{vmatrix} 0 & (a-b)^2 & (a-c)^2 \\ (b-a)^2 & 0 & (b-c)^2 \\ (c-a)^2 & (c-b)^2 & 0 \end{vmatrix} is equal to:
View solution →
hard
If 0<θ<π20 < \theta < \dfrac{\pi}{2} and 1+sin2θcos2θ4sin4θsin2θ1+cos2θ4sin4θsin2θcos2θ1+4sin4θ=0\begin{vmatrix} 1+\sin^2\theta & \cos^2\theta & 4\sin4\theta \\ \sin^2\theta & 1+\cos^2\theta & 4\sin4\theta \\ \sin^2\theta & \cos^2\theta & 1+4\sin4\theta \end{vmatrix} = 0, then θ\theta equals:
View solution →
hard
The determinant Δ=1+xsinαcos(x+α)sin(x+α)13+xsinβcos(x+β)sin(x+β)12+xsinγcos(x+γ)sin(x+γ)\Delta = \begin{vmatrix} -1+x\sin\alpha & \cos(x+\alpha) & \sin(x+\alpha) \\ 13+x\sin\beta & \cos(x+\beta) & \sin(x+\beta) \\ -12+x\sin\gamma & \cos(x+\gamma) & \sin(x+\gamma) \end{vmatrix} is independent of:
View solution →
medium
Let AA and BB be two non-singular matrices of order 2 such that
9A2B6AB+B=9{B(2321)}9A^2B - 6AB + B = 9\left\{B - \begin{pmatrix} 2 & -3 \\ 2 & 1 \end{pmatrix}\right\}
If B=(3011)B = \begin{pmatrix} 3 & 0 \\ 1 & 1 \end{pmatrix} and Tr(A)=103\text{Tr}(A) = \dfrac{10}{3}, then the value of det(A)\det(A) can be:
View solution →
medium
If AA and BB are square matrices of order 3 such that det(A)=2\det(A) = -2 and det(B)=1\det(B) = 1, then det(A1adj(B1)adj(2A1))\det\big(A^{-1}\,\text{adj}(B^{-1})\,\text{adj}(2A^{-1})\big) is equal to:
View solution →
medium
If M=(112021102)M = \begin{pmatrix} 1 & 1 & 2 \\ 0 & 2 & 1 \\ 1 & 0 & 2 \end{pmatrix} and M3=(αMI)(βMI)M^3 = (\alpha M - I)(\beta M - I), where α,β\alpha, \beta are integers and II is the 3×33\times 3 identity matrix, then (α+β)(\alpha + \beta) equals:
View solution →
medium
If AA and BB are two non-singular matrices of order 3 such that AAT=2IAA^T = 2I and A1=ATAadj(2B1)A^{-1} = A^T - A\,\text{adj}(2B^{-1}), then det(B)\det(B) equals:
View solution →
medium
For θ=3π5\theta = \dfrac{3\pi}{5}, let B=[bij]B = [b_{ij}] be a square matrix of order 2 such that bij={cosθ,i=jcos(jπ2+θ),i>jsin(jπ2θ),i<jb_{ij} = \begin{cases} \cos\theta, & i = j \\ \cos\left(\frac{j\pi}{2}+\theta\right), & i > j \\ \sin\left(\frac{j\pi}{2}-\theta\right), & i < j \end{cases}. Then the trace of B5B^5 is:
View solution →
medium
If α,β,γ\alpha, \beta, \gamma are the roots of x3+ax2+bx+c=0x^3+ax^2+bx+c=0 and if the system αu+βv+γw=0\alpha u+\beta v+\gamma w = 0, βu+γv+αw=0\beta u+\gamma v+\alpha w = 0, γu+αv+βw=0\gamma u+\alpha v+\beta w = 0 possesses non-zero solutions, and a36c=0a^3-6c=0, then 2c2c equals:
View solution →
medium
Let M=(0ii0)M = \begin{pmatrix} 0 & i \\ i & 0 \end{pmatrix}, where i2=1i^2 = -1, and let I=(1001)I = \begin{pmatrix} 1 & 0 \\ 0 & 1 \end{pmatrix}. Then I+M+M2+M3++M2010I + M + M^2 + M^3 + \cdots + M^{2010} is equal to:
View solution →
medium
The total number of roots of x1111x1111x1=0\begin{vmatrix} x-1 & 1 & 1 \\ 1 & x-1 & 1 \\ 1 & 1 & x-1 \end{vmatrix} = 0 is:
View solution →
medium
Let A=(221252122)A = \begin{pmatrix} 2 & 2 & 1 \\ 2 & 5 & 2 \\ 1 & 2 & 2 \end{pmatrix} and B=(xyz0y2zxyz)B = \begin{pmatrix} -x & -y & z \\ 0 & y & 2z \\ x & -y & z \end{pmatrix} where x,y,zRx, y, z \in \mathbb{R}. If BTAB=(80002700042)B^T A B = \begin{pmatrix} 8 & 0 & 0 \\ 0 & 27 & 0 \\ 0 & 0 & 42 \end{pmatrix}, then the number of ordered triplets (x,y,z)(x, y, z) is:
View solution →
medium
The value of the determinant a+b+2cabcb+c+2abcac+a+2b\begin{vmatrix} a+b+2c & a & b \\ c & b+c+2a & b \\ c & a & c+a+2b \end{vmatrix} is:
View solution →
medium
Matrix AA is given by A=(31128)A = \begin{pmatrix} 3 & 11 \\ 2 & 8 \end{pmatrix}. Then the determinant of A20115A2010A^{2011} - 5A^{2010} is:
View solution →
medium
AA is a 2×22\times 2 matrix such that A(11)=(12)A\begin{pmatrix}1\\-1\end{pmatrix} = \begin{pmatrix}-1\\2\end{pmatrix} and A2(11)=(10)A^2\begin{pmatrix}1\\-1\end{pmatrix} = \begin{pmatrix}1\\0\end{pmatrix}. The sum of the elements of AA is:
View solution →
medium
In a square matrix AA of order 3, the diagonal elements aiia_{ii} are the sum of the roots of the equation x2(a+b)x+ab=0x^2 - (a+b)x + ab = 0; ai,i+1a_{i,i+1} are the product of the roots of the same equation; ai+1,i=1a_{i+1,i} = 1 for all valid ii; and the remaining elements are zero. The value of det(A)\det(A) is:
View solution →
medium
For a matrix A=(12r101)A = \begin{pmatrix}1 & 2r-1\\ 0 & 1\end{pmatrix}, the value of r=150(12r101)\displaystyle\prod_{r=1}^{50}\begin{pmatrix}1 & 2r-1\\ 0 & 1\end{pmatrix} is equal to:
View solution →
medium
Consider a matrix A=(3162)A = \begin{pmatrix}3 & 1\\ -6 & -2\end{pmatrix}, then (1+A)99(1+A)^{99} equals, where II is a unit matrix of order 2:
View solution →
medium
Let A=(207010121)A = \begin{pmatrix}2 & 0 & 7\\ 0 & 1 & 0\\ 1 & -2 & 1\end{pmatrix} and B=(α14α7α010α4α2α)B = \begin{pmatrix}-\alpha & 14\alpha & 7\alpha\\ 0 & 1 & 0\\ \alpha & -4\alpha & -2\alpha\end{pmatrix}. If AB=IAB = I, where II is the identity matrix of order 3, then the trace of BB equals:
View solution →
medium
If the product of nn matrices (1101)(1201)(1301)(1n01)\begin{pmatrix}1 & 1\\ 0 & 1\end{pmatrix}\begin{pmatrix}1 & 2\\ 0 & 1\end{pmatrix}\begin{pmatrix}1 & 3\\ 0 & 1\end{pmatrix}\cdots\begin{pmatrix}1 & n\\ 0 & 1\end{pmatrix} equals the matrix (137801)\begin{pmatrix}1 & 378\\ 0 & 1\end{pmatrix}, then nn is equal to:
View solution →
medium
If A=(abcd)A = \begin{pmatrix}a & b\\ c & d\end{pmatrix} satisfies the equation x2(a+d)x+k=0x^2 - (a+d)x + k = 0, then:
View solution →
medium
Let AA and BB be square matrices such that AB=0AB = 0 and BB is non-singular. Then:
View solution →
medium
The number of solutions of the matrix equation X2=IX^2 = I other than II is:
View solution →
medium
Number of real values of xx for which the matrix A=(3x2224x1241x)A = \begin{pmatrix}3-x & 2 & 2\\ 2 & 4-x & 1\\ -2 & -4 & -1-x\end{pmatrix} is singular, is:
View solution →
medium
If AA is a diagonal matrix of order 3×33\times 3 that is commutative with every square matrix of order 3×33\times 3 under multiplication and tr(A)=12\text{tr}(A) = 12, then:
View solution →
medium
If A=(1321212)A = \begin{pmatrix}-1 & \dfrac{3}{2}\\[4pt] -\dfrac{1}{2} & \dfrac{1}{2}\end{pmatrix}, then I+A+A2+I + A + A^2 + \cdots\infty is equal to:
View solution →
medium
For positive numbers x,y,zx, y, z, the value of the determinant
1logxylogxzlogyx1logyzlogzxlogzy1\begin{vmatrix} 1 & \log_x y & \log_x z \\ \log_y x & 1 & \log_y z \\ \log_z x & \log_z y & 1 \end{vmatrix}
is:
View solution →
medium
If x,y,zx, y, z are in A.P., then the value of the determinant
456x567y678zxyz0\begin{vmatrix} 4 & 5 & 6 & x \\ 5 & 6 & 7 & y \\ 6 & 7 & 8 & z \\ x & y & z & 0 \end{vmatrix}
is:
View solution →
medium
If f(θ)=cos2θcosθsinθsinθcosθsinθsin2θcosθsinθcosθ0f(\theta) = \begin{vmatrix} \cos^2\theta & \cos\theta\sin\theta & -\sin\theta \\ \cos\theta\sin\theta & \sin^2\theta & \cos\theta \\ \sin\theta & -\cos\theta & 0 \end{vmatrix}, then:
View solution →
medium
Let f(x)=x3sinxcosx610pp2p3f(x) = \begin{vmatrix} x^3 & \sin x & \cos x \\ 6 & -1 & 0 \\ p & p^2 & p^3 \end{vmatrix}, where pp is a constant. Then d3dx3[f(x)]x=0\dfrac{d^3}{dx^3}[f(x)]\big|_{x=0} is:
View solution →
medium
If 32+k4232+3+k42+k5242+4+k52+k6252+5+k=0\begin{vmatrix} 3^2+k & 4^2 & 3^2+3+k \\ 4^2+k & 5^2 & 4^2+4+k \\ 5^2+k & 6^2 & 5^2+5+k \end{vmatrix} = 0, then the value of kk is:
View solution →
medium
If Δ1=xbbaxbaax\Delta_1 = \begin{vmatrix} x & b & b \\ a & x & b \\ a & a & x \end{vmatrix} and Δ2=xbax\Delta_2 = \begin{vmatrix} x & b \\ a & x \end{vmatrix}, then:
View solution →
medium
The value of the determinant (for nNn \in \mathbb{N})
Δ=n!(n+1)!(n+2)!(n+1)!(n+2)!(n+3)!(n+2)!(n+3)!(n+4)!\Delta = \begin{vmatrix} n! & (n+1)! & (n+2)! \\ (n+1)! & (n+2)! & (n+3)! \\ (n+2)! & (n+3)! & (n+4)! \end{vmatrix}
is:
View solution →
medium
If x2+xx+1x22x2+3x13x3x3x2+2x+32x12x1=Px12\begin{vmatrix} x^2+x & x+1 & x-2 \\ 2x^2+3x-1 & 3x & 3x-3 \\ x^2+2x+3 & 2x-1 & 2x-1 \end{vmatrix} = Px - 12, then:
View solution →
medium
The number of distinct real roots of the equation
x2(x1)2(x2)2(x1)2(x2)2(x3)2(x2)2(x3)2(x4)2=0\begin{vmatrix} x^2 & (x-1)^2 & (x-2)^2 \\ (x-1)^2 & (x-2)^2 & (x-3)^2 \\ (x-2)^2 & (x-3)^2 & (x-4)^2 \end{vmatrix} = 0
is:
View solution →
easy
Let AA be a matrix of order 3 defined by A=[aij]3×3A = [a_{ij}]_{3\times 3}, where aij=limx0sin(ix)tan(jx)a_{ij} = \displaystyle\lim_{x \to 0}\frac{\sin(ix)}{\tan(jx)} for all 1i,j31 \le i, j \le 3. Then A2A^2 is:
View solution →
easy
If AA is a 3×33 \times 3 matrix and detA=5\det A = 5, then det(Adj(AdjA))\det\big(\text{Adj}(\text{Adj}\,A)\big) equals:
View solution →
easy
The equation (12213434k)(xyz)=(000)\begin{pmatrix} 1 & 2 & 2 \\ 1 & 3 & 4 \\ 3 & 4 & k \end{pmatrix}\begin{pmatrix} x \\ y \\ z \end{pmatrix} = \begin{pmatrix} 0 \\ 0 \\ 0 \end{pmatrix} has a solution (x,y,z)(x, y, z) besides (0,0,0)(0, 0, 0). The value of kk equals:
View solution →
easy
If MM is a square matrix of order 2, then (tr(M))2tr(M2)(\text{tr}(M))^2 - \text{tr}(M^2) is equal to:
View solution →
easy
AA is an involutory matrix given by A=(011434334)A = \begin{pmatrix}0 & 1 & -1\\ 4 & -3 & 4\\ 3 & -3 & 4\end{pmatrix}, then the inverse of A2\dfrac{A}{2} will be:
View solution →
easy
A square matrix PP satisfies P2=IPP^2 = I - P, where II is the identity matrix. If Pn=5I8PP^n = 5I - 8P, then nn is:
View solution →
easy
Find the roots of the equation
xα1βx1βγ1=0\begin{vmatrix} x & \alpha & 1 \\ \beta & x & 1 \\ \beta & \gamma & 1 \end{vmatrix} = 0
View solution →
easy
If f(x)=1xx+12xx(x1)(x+1)x3x(x1)x(x1)(x2)(x+1)x(x1)f(x) = \begin{vmatrix} 1 & x & x+1 \\ 2x & x(x-1) & (x+1)x \\ 3x(x-1) & x(x-1)(x-2) & (x+1)x(x-1) \end{vmatrix}, then f(100)f(100) is equal to:
View solution →

Practice Matrices & Determinants interactively

Sign up free to practice Matrices & Determinants with timed drills, instant solutions, bookmarks, and chapter-wise progress tracking on doMath.