Matrices & DeterminantseasyFree

Matrices & Determinants — JEE Maths practice question

JEE Maths question with a full step-by-step solution.

Question
Let AA be a matrix of order 3 defined by A=[aij]3×3A = [a_{ij}]_{3\times 3}, where aij=limx0sin(ix)tan(jx)a_{ij} = \displaystyle\lim_{x \to 0}\frac{\sin(ix)}{\tan(jx)} for all 1i,j31 \le i, j \le 3. Then A2A^2 is:
A4A4A
B3A3Acorrect
C2A2A
DAA
Solution
Step 1: Identify the entries
limx0sin(ix)tan(jx)=ij    aij=ij\lim_{x \to 0}\frac{\sin(ix)}{\tan(jx)} = \frac{i}{j} \implies a_{ij} = \frac{i}{j}
Step 2: Compute a general entry of A2A^2
(A2)ik=j=13aijajk=j=13ijjk=j=13ik=3ik=3aik(A^2)_{ik} = \sum_{j=1}^{3} a_{ij}\,a_{jk} = \sum_{j=1}^{3}\frac{i}{j}\cdot\frac{j}{k} = \sum_{j=1}^{3}\frac{i}{k} = 3\cdot\frac{i}{k} = 3\,a_{ik}
Therefore A2=3AA^2 = 3A. Answer: (2)
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