Matrices & DeterminantsmediumFree

Matrices & Determinants: Number Solutions Matrix Equation Other

JEE Maths question with a full step-by-step solution.

Question
The number of solutions of the matrix equation X2=IX^2 = I other than II is:
A00
B11
C22
Dmore than 22correct
Solution
Step 1: Set up the system for a 2×22\times 2 matrix XX Let X=(abcd)X = \begin{pmatrix}a & b\\ c & d\end{pmatrix}. Then X2=IX^2 = I gives:
a2+bc=1,b(a+d)=0,c(a+d)=0,d2+bc=1a^2+bc = 1, \quad b(a+d) = 0, \quad c(a+d) = 0, \quad d^2+bc = 1
Step 2: Analyse Case a=da = -d The conditions b(a+d)=0b(a+d)=0 and c(a+d)=0c(a+d)=0 are satisfied for all b,cb, c. The remaining condition is a2+bc=1a^2+bc = 1. Setting a=0a = 0 (hence d=0d = 0) requires bc=1bc = 1, which is satisfied by any b0b \neq 0 with c=1bc = \frac{1}{b}. For example:
X=(0110),X=(02120),X=I,X = \begin{pmatrix}0 & 1\\ 1 & 0\end{pmatrix}, \quad X = \begin{pmatrix}0 & 2\\ \tfrac{1}{2} & 0\end{pmatrix}, \quad X = -I, \ldots
This yields infinitely many solutions, hence more than 22 solutions other than II. Answer: (4)
Still stuck on this question?Ask your doubt on WhatsApp
Similar questions
Matrices & Determinants · hard
Let AA be a 3×33\times3 matrix such that AT[101]=[522]A^T\begin{bmatrix}1\\0\\1\end{bmatrix}=\begin{bmatrix}5\\2\\2\end{bmatrix}, AT[001]=[311]A^T\begin{bmatrix}0\\0\\1\end{bmatrix}=\begin{bmatrix}3\\1\\1\end{bmatrix}, A[101]=[344]A\begin{bmatrix}1\\0\\1\end{bmatrix}=\begin{bmatrix}3\\4\\4\end{bmatrix} and A[001]=[131]A\begin{bmatrix}0\\0\\1\end{bmatrix}=\begin{bmatrix}1\\3\\1\end{bmatrix}. If det(A)=1\det(A)=1, then det(adj(A2+A))\det\big(\mathrm{adj}(A^2+A)\big) is equal to
Matrices & Determinants · medium
Let MM be a 3×33\times3 matrix such that M(100)=(123)M\begin{pmatrix}1\\0\\0\end{pmatrix}=\begin{pmatrix}1\\2\\3\end{pmatrix}, M(010)=(012)M\begin{pmatrix}0\\1\\0\end{pmatrix}=\begin{pmatrix}0\\1\\2\end{pmatrix}, and M(001)=(111)M\begin{pmatrix}0\\0\\1\end{pmatrix}=\begin{pmatrix}-1\\1\\1\end{pmatrix}. If M(xyz)=(1711)M\begin{pmatrix}x\\y\\z\end{pmatrix}=\begin{pmatrix}1\\7\\11\end{pmatrix}, then x+y+zx+y+z equals:
Matrices & Determinants · medium
If f:NZf:\mathbb{N} \to \mathbb{Z} is defined by f(n)=n152n23(2k+1)2k+13n33k(2k+1)3k(k+2)+1,kNf(n) = \begin{vmatrix} n & -1 & -5 \\ -2n^2 & 3(2k+1) & 2k+1 \\ -3n^3 & 3k(2k+1) & 3k(k+2)+1 \end{vmatrix}, \quad k \in \mathbb{N} and n=1kf(n)=98\displaystyle\sum_{n=1}^k f(n) = 98, then kk is equal to:
Matrices & Determinants · hard
If f(x)=x5sinx2x4tan3x1sec2xsin3xx45f(x) = \begin{vmatrix} x^5 & |\sin x| & 2x^4 \\ \tan^3 x & 1 & \sec 2x \\ \sin^3 x & x^4 & 5 \end{vmatrix}, then π/2π/2f(x)dx\displaystyle\int_{-\pi/2}^{\pi/2} f(x)\,dx is equal to:

Solve more, learn faster

Sign up free to solve more JEE Maths questions and explore doMath — timed drills, mastery sprints, bookmarks, and chapter-wise progress tracking.