Sequences & Series50 questions3 PYQ

Sequences & SeriesJEE Maths Practice Questions & Solutions

50 questions on Sequences & Series with full step-by-step solutions, including past-year (PYQ) problems. Free to practice.

mediumPYQ · JEE Main 2026
Let α,β\alpha, \beta be the roots of x2x+p=0x^2 - x + p = 0 and γ,δ\gamma, \delta be the roots of x24x+q=0x^2 - 4x + q = 0, where p,qZp, q \in \mathbb{Z}. If α,β,γ,δ\alpha, \beta, \gamma, \delta are in G.P., then p+q|p + q| equals:
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mediumPYQ · JEE Main 2026
If the sum of the first 10 terms of the series 11+144+21+244+31+344+\dfrac{1}{1+1^4\cdot4}+\dfrac{2}{1+2^4\cdot4}+\dfrac{3}{1+3^4\cdot4}+\cdots is mn\dfrac{m}{n} with gcd(m,n)=1\gcd(m,n)=1, then m+nm+n is equal to:
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mediumPYQ · JEE Main 2026
Let A1,A2,,A39A_1, A_2, \ldots, A_{39} be 39 arithmetic means between 59 and 159. Then the mean of A25A_{25}, A28A_{28}, A31A_{31} and A36A_{36} is equal to:
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hard
The value of n=12008n4+2n3+3n2+2n+1n(n+1)\displaystyle\sum_{n=1}^{2008}\frac{\sqrt{n^4+2n^3+3n^2+2n+1}}{n(n+1)} is
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hard
Consider ax2bx+c=0ax^2-bx+c=0 with a,b,cNa, b, c\in\mathbb{N}. If it has two distinct real roots in (1,2)(1,2), then
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medium
Let a1,a2,,a4001a_1, a_2, \ldots, a_{4001} be in A.P. such that 1a1a2+1a2a3++1a4000a4001=10\frac{1}{a_1 a_2}+\frac{1}{a_2 a_3}+\cdots+\frac{1}{a_{4000} a_{4001}}=10 and a2+a4000=50a_2+a_{4000}=50. Then a1a4001|a_1-a_{4001}| equals
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medium
If p+q5xpq5x=q+r5xqr5x=r+s5xrs5x\frac{p+q\cdot 5^x}{p-q\cdot 5^x}=\frac{q+r\cdot 5^x}{q-r\cdot 5^x}=\frac{r+s\cdot 5^x}{r-s\cdot 5^x}, then p,q,r,sp, q, r, s are in
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medium
The largest term of the sequence 1503,4524,9581,16692,\frac{1}{503},\frac{4}{524},\frac{9}{581},\frac{16}{692},\ldots is
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medium
A sequence AnA_n is defined by A1=12A_1=\frac12 and An=2n32nAn1A_n=\frac{2n-3}{2n}A_{n-1} for n2n\ge 2. Then
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medium
The sequence {xn}\{x_n\} is defined by xk+1=xk2+xkx_{k+1}=x_k^2+x_k and x1=12x_1=\frac12. Then [1x1+1+1x2+1++1x100+1]\left[\frac{1}{x_1+1}+\frac{1}{x_2+1}+\cdots+\frac{1}{x_{100}+1}\right], where [][\,\cdot\,] is the greatest integer function, equals
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medium
If a,b,c,da, b, c, d are positive reals with abcd=1abcd=1, then the minimum value of (1+a)(1+b)(1+c)(1+d)(1+a)(1+b)(1+c)(1+d) is
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medium
Let a1,a2,a3,a4,a5a_1, a_2, a_3, a_4, a_5 be five terms of a geometric sequence satisfying
0<a1<a2<a3<a4<a5<1000<a_1<a_2<a_3<a_4<a_5<100
where each term is an integer. Then the number of such geometric progressions is
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medium
If a1,a2,,ana_1, a_2, \ldots, a_n are distinct odd natural numbers not divisible by any prime greater than 55, then
1a1+1a2++1an\frac{1}{a_1}+\frac{1}{a_2}+\cdots+\frac{1}{a_n}
is less than
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medium
If a,b,c,da, b, c, d are in G.P., then (a2+b2+c2)(b2+c2+d2)(a^2+b^2+c^2)(b^2+c^2+d^2) equals
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medium
If ai>0a_i>0 for 1i51\le i\le 5 and a1a2a3a4a5=6a_1 a_2 a_3 a_4 a_5=6, then the least value of a1+2a2+3a3+4a4+5a5a_1+2a_2+3a_3+4a_4+5a_5 is
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medium
If a,b,ca, b, c are positive with a+b+c=6a+b+c=6, then the minimum value of (a+1b)2+(b+1c)2+(c+1a)2\left(a+\frac1b\right)^2+\left(b+\frac1c\right)^2+\left(c+\frac1a\right)^2 is
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medium
The sum of the series 419+44192+444193+\frac{4}{19}+\frac{44}{19^2}+\frac{444}{19^3}+\cdots to infinity is
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medium
If a+b+c+d+e=8a+b+c+d+e=8 and a2+b2+c2+d2+e2=16a^2+b^2+c^2+d^2+e^2=16, where a,b,c,d,ea,b,c,d,e are non-negative reals and the range of ee is [,mn]\left[\ell,\frac{m}{n}\right] with gcd(m,n)=1\gcd(m,n)=1, then +m+n\ell+m+n is
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medium
If A,G,HA, G, H are respectively the A.M., G.M. and H.M. between two positive numbers, and xA=yG=zHxA=yG=zH where x,y,zx, y, z are non-zero positive quantities, then x,y,zx, y, z are in
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medium
The 20082008th term of the sequence 1, 2,2,2, 3,3,3,3,3,3, 4,1,\ 2,2,2,\ 3,3,3,3,3,3,\ 4,\ldots where nn occurs n(n+1)2\frac{n(n+1)}{2} times, equals
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medium
If H1,H2,,H20H_1, H_2, \ldots, H_{20} are 2020 harmonic means between 22 and 33, then H1+2H12+H20+3H203=\frac{H_1+2}{H_1-2}+\frac{H_{20}+3}{H_{20}-3}=
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medium
If 112+122+132+=π26\frac{1}{1^2}+\frac{1}{2^2}+\frac{1}{3^2}+\cdots=\frac{\pi^2}{6}, then 112+132+152+\frac{1}{1^2}+\frac{1}{3^2}+\frac{1}{5^2}+\cdots is equal to
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medium
In a sequence of (4n+1)(4n+1) terms, the first (2n+1)(2n+1) terms are in A.P. with common difference 22, and the last (2n+1)(2n+1) terms are in G.P. with common ratio 0.50.5. If the middle terms of the A.P. and the G.P. are equal, then the middle term of the sequence is
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medium
The sum of the series x1x2+x21x4+x41x8+\frac{x}{1-x^2}+\frac{x^2}{1-x^4}+\frac{x^4}{1-x^8}+\cdots to infinity, for x<1|x|<1, is
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medium
If nn arithmetic means are inserted between aa and 2b2b, and also between 2a2a and bb (a,bRa,b\in\mathbb{R}), and the mmth means of the two sets are equal, then a:ba:b equals
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medium
If a,b,ca, b, c are in A.P., p,pp, p' are the A.M. and G.M. between aa and bb, and q,qq, q' are the A.M. and G.M. between bb and cc, then
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medium
Through the centroid of an equilateral triangle a line parallel to the base is drawn. On this line an arbitrary interior point PP is taken. Let hh be the distance of PP from the base, and h1,h2h_1, h_2 its distances from the other two sides. Then
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easy
a,b,c,da, b, c, d are in increasing G.P. If the A.M. between aa and bb is 66 and the A.M. between cc and dd is 5454, then the A.M. of aa and dd is
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easy
Let a1,a2,a_1, a_2, \ldots and b1,b2,b_1, b_2, \ldots be arithmetic progressions with a1=25a_1=25, b1=75b_1=75 and a100+b100=100a_{100}+b_{100}=100. Then the sum of the first hundred terms of a1+b1, a2+b2, a_1+b_1,\ a_2+b_2,\ \ldots is
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easy
If Sn=1123+1234++1n(n+1)(n+2)S_n=\frac{1}{1\cdot2\cdot3}+\frac{1}{2\cdot3\cdot4}+\cdots+\frac{1}{n(n+1)(n+2)}, then 8S8S_\infty is
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easy
If the sum to infinity of 1+4x+7x2+10x3+1+4x+7x^2+10x^3+\cdots is 3516\frac{35}{16}, where x<1|x|<1, then xx equals
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easy
If tr=12+22++r213+23++r3t_r=\frac{1^2+2^2+\cdots+r^2}{1^3+2^3+\cdots+r^3} and Sn=r=1n(1)rtrS_n=\sum_{r=1}^{n}(-1)^r t_r, then limnSn\lim_{n\to\infty}S_n equals
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easy
If Sn=123!+2224!+3235!+S_n=\frac{1\cdot2}{3!}+\frac{2\cdot2^2}{4!}+\frac{3\cdot2^3}{5!}+\cdots up to nn terms, then the sum to infinite terms is
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easy
The sum of the first nn terms (n>1n>1) of an A.P. is 153153 and the common difference is 22. If the first term is an integer, the number of possible values of nn is
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easy
If the lengths of the sides of a right triangle are in A.P., then the sines of the acute angles are
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easy
If a right triangle has sides in AP, solving Pythagoras gives ratio 3:4:5, so the acute angle sines are 3/5 and 4/5
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easy
Let f(n),g(n)f(n), g(n) denote the sums of nn terms of the sequences 2,5,10,17,26,2,5,10,17,26,\ldots and 2,6,12,20,2,6,12,20,\ldots respectively. Then limnf(n)g(n)\lim_{n\to\infty}\frac{f(n)}{g(n)} is
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easy
Consider α0,α1,α2,\alpha_0, \alpha_1, \alpha_2, \ldots with α0=17.23\alpha_0=17.23, α1=33.23\alpha_1=33.23 and αr+2=αr+αr+12\alpha_{r+2}=\frac{\alpha_r+\alpha_{r+1}}{2} for all r0r\ge 0. The value of α10α9|\alpha_{10}-\alpha_9| is
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easy
If 113+1517+19111+=π41-\frac13+\frac15-\frac17+\frac19-\frac{1}{11}+\cdots=\frac{\pi}{4}, then the value of 113+157+1911+\frac{1}{1\cdot3}+\frac{1}{5\cdot7}+\frac{1}{9\cdot11}+\cdots is
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easy
If a,b,ca, b, c are three positive numbers, then the minimum value of ab(a+b)+bc(b+c)+ca(c+a)abc\frac{ab(a+b)+bc(b+c)+ca(c+a)}{abc} is
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easy
If the sum of nn terms of an A.P. is cn(n1)cn(n-1) with c0c\ne 0, then the sum of the squares of these terms is
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easy
If a,b,ca, b, c are three distinct numbers such that a,b,ca, b, c are in A.P. and ba, cb, ab-a,\ c-b,\ a are in G.P., then a:b:ca:b:c is
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easy
If ak=1k(k+1)a_k=\frac{1}{k(k+1)} for k=1,2,,nk=1,2,\ldots,n, then (k=1nak)2\left(\sum_{k=1}^{n}a_k\right)^2 is equal to
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easy
The value of the series is k=11k!(n=1k2n1)\displaystyle\sum_{k=1}^{\infty}\frac{1}{k!}\left(\sum_{n=1}^{k}2^{n-1}\right)
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easy
If 1, log93x+48, log9(3x83)1,\ \log_9\sqrt{3^x+48},\ \log_9\left(3^x-\frac83\right) are in A.P., then the value of xx is
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easy
If a,b,ca, b, c are in H.P., then ab+c, bc+a, ca+b\frac{a}{b+c},\ \frac{b}{c+a},\ \frac{c}{a+b} are in
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easy
The ratio of the sum of the first three terms of a G.P. to the sum of the first six terms is 64:9164:91. The common ratio of the G.P. is
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easy
The sum of the series 3+5+9+17+33+3+5+9+17+33+\cdots to nn terms is
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easy
If one A.M. AA and two G.M.s pp and qq are inserted between two numbers aa and bb, then which is true?
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easy
If the fourth term of a G.P. is 33, then the product of the first seven terms is
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