Matrices & DeterminantsmediumPYQ · JEE Main · 2 Apr 2026 · Shift 2 (Afternoon)Free

System with Infinite Solutions: Point (a,b) on x - y = 3 | JEE 2026

JEE Maths question with a full step-by-step solution.

Question
If the system of equations
x+5y+6z=4,2x+3y+4z=7,x+6y+az=bx+5y+6z=4,\quad 2x+3y+4z=7,\quad x+6y+az=b
has infinitely many solutions, then the point (a,b)(a,b) lies on the line
Ayx=3y-x=3
Bxy=3x-y=3correct
Cx+y=11x+y=11
Dx+y=12x+y=12
Solution
Step 1: For infinitely many solutions the determinant of coefficients must vanish:
D=15623416a=0.D=\begin{vmatrix}1&5&6\\2&3&4\\1&6&a\end{vmatrix}=0.
Expanding gives
a=507.a=\frac{50}{7}.
Step 2: Also Dz=0D_z=0 (replacing the third column by the constants):
Dz=15423716b=0  b=297.D_z=\begin{vmatrix}1&5&4\\2&3&7\\1&6&b\end{vmatrix}=0\ \Rightarrow\ b=\frac{29}{7}.
Step 3: Then
ab=507297=217=3,a-b=\frac{50}{7}-\frac{29}{7}=\frac{21}{7}=3,
so the point (a,b)(a,b) lies on the line xy=3x-y=3. Correct answer: (2)
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