FunctionseasyFree

Functions — JEE Maths practice question

JEE Maths question with a full step-by-step solution.

Question
The number of integers in the domain of f(x)=1lncos1xf(x) = \dfrac{1}{\sqrt{\ln\cos^{-1}x}}.
Solution
Answer: 2
Step 1: Determine when the expression under the square root is positive
lncos1x>0    cos1x>e0=1\ln\cos^{-1}x > 0 \implies \cos^{-1}x > e^0 = 1
Step 2: Find the range of xx Since cos1x[0,π]\cos^{-1}x \in [0, \pi], the condition cos1x>1\cos^{-1}x > 1 gives:
1<cos1xπ    1x<cos10.541 < \cos^{-1}x \leq \pi \implies -1 \leq x < \cos 1 \approx 0.54
Step 3: Count integers in [1,cos1)[-1, \cos 1) The integers in this interval are 1-1 and 00. Number of integers = 2. Answer: 2
Still stuck on this question?Ask your doubt on WhatsApp
Similar questions

Solve more, learn faster

Sign up free to solve more JEE Maths questions and explore doMath — timed drills, mastery sprints, bookmarks, and chapter-wise progress tracking.