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Parallelogram Condition for a+i, a−i, 1+ai, 1−ai | JEE

JEE Maths question with a full step-by-step solution.

Question
The complex numbers a+ia + i, aia - i, 1+ai1 + ai and 1ai1 - ai, where aRa \in \mathbb{R}, taken in that order on the Argand plane, represent the vertices of a parallelogram if
Aa=1a = 1
Ba=1a = -1correct
Ca=0a = 0
Dnone of these
Solution
Step 1: Label the vertices in order: A=a+iA = a + i, B=aiB = a - i, C=1+aiC = 1 + ai, D=1aiD = 1 - ai. Step 2: Use the parallelogram diagonal property. In a parallelogram ABCDABCD, the diagonals ACAC and BDBD bisect each other, so their midpoints coincide:
A+C2=B+D2    A+C=B+D\frac{A + C}{2} = \frac{B + D}{2} \implies A + C = B + D
Step 3: Compute both sides.
A+C=(a+i)+(1+ai)=(a+1)+(1+a)iA + C = (a + i) + (1 + ai) = (a + 1) + (1 + a)i
B+D=(ai)+(1ai)=(a+1)(1+a)iB + D = (a - i) + (1 - ai) = (a + 1) - (1 + a)i
Step 4: Set them equal. The real parts (a+1)(a + 1) already match. Equate the imaginary parts:
(1+a)=(1+a)    2(1+a)=0    a=1(1 + a) = -(1 + a) \implies 2(1 + a) = 0 \implies a = -1
Step 5: Check a=1a = -1 gives genuine (non-degenerate) vertices: A=1+iA = -1 + i, B=1iB = -1 - i, C=1iC = 1 - i, D=1+iD = 1 + i — these are four distinct points forming a square (a special parallelogram). Valid. Correct answer: (2)
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