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Find n from Overlapping Sets A and B Membership Counts | JEE

JEE Maths question with a full step-by-step solution.

Question
Suppose A1,A2,,A30A_1, A_2, \ldots, A_{30} are thirty sets each having 55 elements and B1,B2,,BnB_1, B_2, \ldots, B_n are nn sets each with 33 elements. Let i=130Ai=j=1nBj=S\bigcup_{i=1}^{30} A_i = \bigcup_{j=1}^{n} B_j = S, and each element of SS belongs to exactly 1010 of the AiA_i and exactly 99 of the BjB_j. Then nn is equal to:
A1515
B33
C4545correct
D3535
Solution
Step 1: Count memberships through the AiA_i. Total =30×5=150= 30 \times 5 = 150, and each element of SS is counted 1010 times:
10n(S)=150n(S)=15.10 \cdot n(S) = 150 \Rightarrow n(S) = 15.
Step 2: Count memberships through the BjB_j. Total =3n= 3n, and each element of SS is counted 99 times:
3n=9n(S)=9×15=135n=45.3n = 9 \cdot n(S) = 9 \times 15 = 135 \Rightarrow n = 45.
Correct answer: (3)
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