Ellipse35 questions2 PYQ

EllipseJEE Maths Practice Questions & Solutions

35 questions on Ellipse with full step-by-step solutions, including past-year (PYQ) problems. Free to practice.

hardPYQ · JEE Main 2026
Let P(3cosα,2sinα)P(3\cos\alpha,2\sin\alpha), α0\alpha\ne0, be a point on the ellipse x29+y24=1\dfrac{x^2}{9}+\dfrac{y^2}{4}=1, QQ a point on the circle x2+y214x14y+82=0x^2+y^2-14x-14y+82=0, and RR a point on the line x+y=5x+y=5, such that the centroid of PQR\triangle PQR is (2+cosα, 3+23sinα)\left(2+\cos\alpha,\ 3+\dfrac23\sin\alpha\right). Then the sum of the ordinates of all possible points RR is
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easyPYQ · JEE Main 2026
Let a focus of the ellipse E:x2a2+y2b2=1E:\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1 be S(4,0)S(4,0) and its eccentricity be 45\dfrac45. If the point P(3,α)P(3,\alpha) lies on EE and OO is the origin, then the area of POS\triangle POS is
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hard
The maximum distance of the centre of the ellipse x216+y29=1\dfrac{x^2}{16}+\dfrac{y^2}{9}=1 from the chord of contact of mutually perpendicular tangents is:
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hard
Two tangents are drawn to the ellipse x2a2+y2b2=1\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1 from the point P(h,k)P(h,k). The points in which these tangents cut the axes are concyclic. The locus of PP is:
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medium
An ellipse having foci at (3,3)(3,3) and (4,4)(-4,4) and passing through the origin has eccentricity equal to:
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medium
The foci of an ellipse are (2,4)(-2,4) and (2,1)(2,1). The point (1,236)\left(1,\dfrac{23}{6}\right) is an extremity of the minor axis. What is the value of the eccentricity?
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medium
An ellipse with major and minor axes of length 10310\sqrt3 and 1010 units slides along the coordinate axes and always remains confined in the first quadrant. The locus of the centre of the ellipse is the arc of a circle. The length of this arc is:
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medium
Let S(3,4)S(3,4) and S(9,12)S'(9,12) be the foci of an ellipse and the foot of the perpendicular from SS to a tangent to the ellipse is (1,4)(1,-4). Then the eccentricity of the ellipse is:
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medium
The line lx+my+n=0lx+my+n=0 cuts the ellipse x2a2+y2b2=1\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1 in points whose eccentric angles differ by π2\dfrac{\pi}{2}, if:
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medium
The normal at a variable point PP on an ellipse x2a2+y2b2=1\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1 of eccentricity ee meets the axes in QQ and RR. Then the locus of the midpoint of QRQR is a conic with eccentricity ee' such that:
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medium
A circle touches the major axes of the two ellipses x22086+y22010=1\dfrac{x^2}{2086}+\dfrac{y^2}{2010}=1 and x22010+y22086=1\dfrac{x^2}{2010}+\dfrac{y^2}{2086}=1 and one of their common tangents, with radius rr. Then [r][r] (greatest integer function) equals:
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medium
In the standard ellipse, the lines joining the ends of the minor axis to one focus are at right angles. The distance between the focus and the nearer vertex is 105\sqrt{10}-\sqrt5. The equation of the ellipse is:
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medium
If the tangent at a point (acosθ,bsinθ)(a\cos\theta,b\sin\theta) on the ellipse x2a2+y2b2=1\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1 meets the auxiliary circle in two points and the chord joining them subtends a right angle at the centre, then the eccentricity is:
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medium
A focal chord through the focus SS meets the ellipse 9x2+16y2=1449x^2+16y^2=144 at PP and QQ. AA and BB are the feet of the perpendiculars from the foci SS and SS' to the tangent at PP, and OO is the centre. Then SP+SQSPSQ+OAOBSASB\dfrac{SP+SQ}{SP\cdot SQ}+\dfrac{OA\cdot OB}{SA\cdot S'B} equals:
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medium
If the ellipse x24+y2=1\dfrac{x^2}{4}+y^2=1 meets the ellipse x2+y2a2=1x^2+\dfrac{y^2}{a^2}=1 in four distinct points and a=b25b+7a=b^2-5b+7, then bb does not lie in:
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medium
If a variable tangent of the circle x2+y2=1x^2+y^2=1 intersects the ellipse x2+2y2=4x^2+2y^2=4 at PP and QQ, then the locus of the point of intersection of the tangents at PP and QQ is:
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medium
A circle S=0S=0 touches the circle x2+y24x+6y23=0x^2+y^2-4x+6y-23=0 internally and the circle x2+y24x+8y+19=0x^2+y^2-4x+8y+19=0 externally. The locus of the centre of S=0S=0 is a conic whose eccentricity is kk. Then [1k]\left[\dfrac1k\right] (greatest integer function) is:
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medium
If the circumcentre of an equilateral triangle inscribed in x2a2+y2b2=1\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1, with vertices having eccentric angles α,β,γ\alpha,\beta,\gamma, is (x1,y1)(x_1,y_1), then cosαcosβ+sinαsinβ\sum\cos\alpha\cos\beta+\sum\sin\alpha\sin\beta is:
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easy
The equation x210a+y24a=1\dfrac{x^2}{10-a}+\dfrac{y^2}{4-a}=1 represents an ellipse if:
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easy
The eccentricity of the ellipse (x3)2+(y4)2=y29(x-3)^2+(y-4)^2=\dfrac{y^2}{9} is:
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easy
An ellipse has foci at (9,20)(9,20) and (49,55)(49,55) in the xyxy-plane and is tangent to the xx-axis. The length of its major axis is:
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easy
If x2f(4a)+y2f(a25)=1\dfrac{x^2}{f(4a)}+\dfrac{y^2}{f(a^2-5)}=1 represents an ellipse with major axis as yy-axis and ff is a decreasing function, then
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easy
If b2=a2(1e2)b^2=a^2(1-e^2), then for any α\alpha, a,bRa,b\in\mathbb{R},
a2cos2α+b2sin2α2a2ecosα+a2e2+a2cos2α+b2sin2α+2a2ecosα+a2e2\sqrt{a^2\cos^2\alpha+b^2\sin^2\alpha-2a^2e\cos\alpha+a^2e^2}+\sqrt{a^2\cos^2\alpha+b^2\sin^2\alpha+2a^2e\cos\alpha+a^2e^2}
is equal to:
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easy
If an ellipse slides on the rectangular coordinate axes and foci of the ellipse are at (2,y1)(2,y_1) and (3,y2)(3,y_2), then y1y2y_1y_2 equals
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easy
The foci of the ellipse 3x24xy+3y2=53x^2-4xy+3y^2=5 are
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easy
The minimum value of {(r+54cosθ)2+(r3sinθ)2}\left\{(r+5-4|\cos\theta|)^2+(r-3|\sin\theta|)^2\right\}, r,θR\forall\,r,\theta\in\mathbb{R}, is:
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easy
The area of the triangle inscribed in an ellipse bears the ratio 5:3\sqrt5:3 to the area of the triangle formed by joining points on the auxiliary circle corresponding to the vertices of the first triangle. Then the eccentricity of the ellipse is:
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easy
Which one of the following is the common tangent to the ellipses x2a2+b2+y2b2=1\dfrac{x^2}{a^2+b^2}+\dfrac{y^2}{b^2}=1 and x2a2+y2a2+b2=1\dfrac{x^2}{a^2}+\dfrac{y^2}{a^2+b^2}=1?
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easy
If tanθ1tanθ2=a2b2\tan\theta_1\tan\theta_2=-\dfrac{a^2}{b^2}, then the chord joining the points θ1\theta_1 and θ2\theta_2 on the ellipse x2a2+y2b2=1\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1 subtends a right angle at:
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easy
Let PP be a point on the ellipse x2a2+y2b2=1 (a>b)\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1\ (a>b) in the first quadrant, whose foci are S1S_1 and S2S_2. Then the least possible value of the circumradius of PS1S2\triangle PS_1S_2 is:
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easy
If CFCF is the perpendicular from the centre CC of the ellipse x2a2+y2b2=1\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1 on the tangent at a point PP, and GG is the point where the normal at PP meets the major axis, then CFPGCF\cdot PG is:
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easy
Tangents are drawn to the ellipse x29+y25=1\dfrac{x^2}{9}+\dfrac{y^2}{5}=1 at the ends of the latus rectum. The area of the quadrilateral so formed is:
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easy
If the ellipse x2a23+y2a+4=1\dfrac{x^2}{a^2-3}+\dfrac{y^2}{a+4}=1 is inscribed in a square of side length a2a\sqrt2 units, then aa is:
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easy
Let there exist at least one normal to an ellipse which touches a concentric circle, and the circle intersects the ellipse at four distinct points. Then the eccentricity of the ellipse is:
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easy
Tangents are drawn from any point on the circle x2+y2=41x^2+y^2=41 to the ellipse x225+y216=1\dfrac{x^2}{25}+\dfrac{y^2}{16}=1. The angle between the two tangents is:
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