Ellipse49 questions3 PYQ

Ellipse — JEE Maths Practice Questions & Solutions

49 questions on Ellipse with full step-by-step solutions, including past-year (PYQ) problems. Free to practice.

hardPYQ · JEE Main 2026
Let P(3cos⁡α,2sin⁡α)P(3\cos\alpha,2\sin\alpha), α≠0\alpha\ne0, be a point on the ellipse x29+y24=1\dfrac{x^2}{9}+\dfrac{y^2}{4}=1, QQ a point on the circle x2+y2−14x−14y+82=0x^2+y^2-14x-14y+82=0, and RR a point on the line x+y=5x+y=5, such that the centroid of △PQR\triangle PQR is (2+cos⁡α, 3+23sin⁡α)\left(2+\cos\alpha,\ 3+\dfrac23\sin\alpha\right). Then the sum of the ordinates of all possible points RR is
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easyPYQ · JEE Main 2026
Let a focus of the ellipse E:x2a2+y2b2=1E:\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1 be S(4,0)S(4,0) and its eccentricity be 45\dfrac45. If the point P(3,α)P(3,\alpha) lies on EE and OO is the origin, then the area of △POS\triangle POS is
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easyPYQ · JEE Main 2026
Let an ellipse x2a2+y2b2=1\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1, a<ba<b, pass through the point (4,3)(4,3) and have eccentricity 53\dfrac{\sqrt5}{3}. Then the length of its latus rectum is
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hard
The maximum distance of the centre of the ellipse x216+y29=1\dfrac{x^2}{16}+\dfrac{y^2}{9}=1 from the chord of contact of mutually perpendicular tangents is:
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hard
Two tangents are drawn to the ellipse x2a2+y2b2=1\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1 from the point P(h,k)P(h,k). The points in which these tangents cut the axes are concyclic. The locus of PP is:
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hard
Three curves are given:
C1:x2−y2=1 (x<0)C_1 : x^{2} - y^{2} = 1 \ (x < 0)
C2:xy=1 (y>0)C_2 : xy = 1 \ (y > 0)
and C3C_3, an ellipse having one focus at a focus of C2C_2, the directrix corresponding to that focus being an asymptote of C1C_1, with the major axis of C3C_3 of length 83\dfrac83. Find the eccentricity of C3C_3.
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hard
The line x2cos⁡θ+y1sin⁡θ=1\dfrac{x}{2}\cos\theta + \dfrac{y}{1}\sin\theta = 1, with θ∈(π18,π15)\theta \in \left(\dfrac{\pi}{18},\dfrac{\pi}{15}\right), meets the ellipse x2+2y2=6x^{2}+2y^{2}=6 at PP and QQ. Find the angle between the tangents to the ellipse at PP and QQ.
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hard
From every point of the line (t+2)(x+y)=1(t+2)(x+y) = 1, t≠−2t \ne -2, tangents are drawn to the ellipse 4x2+16y2=14x^{2} + 16y^{2} = 1, and the chord of contact passes through a fixed point. Find the number of integral values of tt for which this fixed point lies inside the ellipse.
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medium
An ellipse having foci at (3,3)(3,3) and (−4,4)(-4,4) and passing through the origin has eccentricity equal to:
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medium
The foci of an ellipse are (−2,4)(-2,4) and (2,1)(2,1). The point (1,236)\left(1,\dfrac{23}{6}\right) is an extremity of the minor axis. What is the value of the eccentricity?
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medium
An ellipse with major and minor axes of length 10310\sqrt3 and 1010 units slides along the coordinate axes and always remains confined in the first quadrant. The locus of the centre of the ellipse is the arc of a circle. The length of this arc is:
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medium
Let S(3,4)S(3,4) and S′(9,12)S'(9,12) be the foci of an ellipse and the foot of the perpendicular from SS to a tangent to the ellipse is (1,−4)(1,-4). Then the eccentricity of the ellipse is:
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medium
The line lx+my+n=0lx+my+n=0 cuts the ellipse x2a2+y2b2=1\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1 in points whose eccentric angles differ by π2\dfrac{\pi}{2}, if:
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medium
The normal at a variable point PP on an ellipse x2a2+y2b2=1\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1 of eccentricity ee meets the axes in QQ and RR. Then the locus of the midpoint of QRQR is a conic with eccentricity e′e' such that:
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medium
A circle touches the major axes of the two ellipses x22086+y22010=1\dfrac{x^2}{2086}+\dfrac{y^2}{2010}=1 and x22010+y22086=1\dfrac{x^2}{2010}+\dfrac{y^2}{2086}=1 and one of their common tangents, with radius rr. Then [r][r] (greatest integer function) equals:
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medium
In the standard ellipse, the lines joining the ends of the minor axis to one focus are at right angles. The distance between the focus and the nearer vertex is 10−5\sqrt{10}-\sqrt5. The equation of the ellipse is:
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medium
If the tangent at a point (acos⁡θ,bsin⁡θ)(a\cos\theta,b\sin\theta) on the ellipse x2a2+y2b2=1\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1 meets the auxiliary circle in two points and the chord joining them subtends a right angle at the centre, then the eccentricity is:
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medium
A focal chord through the focus SS meets the ellipse 9x2+16y2=1449x^2+16y^2=144 at PP and QQ. AA and BB are the feet of the perpendiculars from the foci SS and S′S' to the tangent at PP, and OO is the centre. Then SP+SQSP⋅SQ+OA⋅OBSA⋅S′B\dfrac{SP+SQ}{SP\cdot SQ}+\dfrac{OA\cdot OB}{SA\cdot S'B} equals:
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medium
If the ellipse x24+y2=1\dfrac{x^2}{4}+y^2=1 meets the ellipse x2+y2a2=1x^2+\dfrac{y^2}{a^2}=1 in four distinct points and a=b2−5b+7a=b^2-5b+7, then bb does not lie in:
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medium
If a variable tangent of the circle x2+y2=1x^2+y^2=1 intersects the ellipse x2+2y2=4x^2+2y^2=4 at PP and QQ, then the locus of the point of intersection of the tangents at PP and QQ is:
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medium
A circle S=0S=0 touches the circle x2+y2−4x+6y−23=0x^2+y^2-4x+6y-23=0 internally and the circle x2+y2−4x+8y+19=0x^2+y^2-4x+8y+19=0 externally. The locus of the centre of S=0S=0 is a conic whose eccentricity is kk. Then [1k]\left[\dfrac1k\right] (greatest integer function) is:
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medium
If the circumcentre of an equilateral triangle inscribed in x2a2+y2b2=1\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1, with vertices having eccentric angles α,β,γ\alpha,\beta,\gamma, is (x1,y1)(x_1,y_1), then ∑cos⁡αcos⁡β+∑sin⁡αsin⁡β\sum\cos\alpha\cos\beta+\sum\sin\alpha\sin\beta is:
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medium
For an ellipse, the minor axis lies along the line x+2y=3x + 2y = 3 and has length 5\sqrt5, and the foot of a directrix is (2,3)(2,3). Then
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medium
The ellipse x216+y2b2=1\dfrac{x^{2}}{16} + \dfrac{y^{2}}{b^{2}} = 1 is inscribed in a square whose side has length 525\sqrt2. Find the area of the ellipse.
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medium
An ellipse has its centre at the origin, and the lines 3x+5y=203x + 5y = 20 and 3x−5y=203x - 5y = 20 touch it at the two ends of a latus rectum. Find the length of that latus rectum.
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medium
For an ellipse, one focus is (2,3)(2,3), the eccentricity is 13\dfrac13, and the corresponding directrix cuts the major axis at (10,11)(10,11). Which of the following statements are correct?
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medium
The minimum value of f(x)=∣x−a∣+2∣x−2∣f(x) = |x-a| + 2|x-2| is 11, and a>2a > 2. Take the ellipse x2a2+y24=1\dfrac{x^{2}}{a^{2}} + \dfrac{y^{2}}{4} = 1 and draw tangents to it from the point P(1,2)P(1,2). If this ellipse has eccentricity ee, then a possible value of ee is
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medium
A tangent PQPQ to the ellipse x2a2+y2b2=1\dfrac{x^{2}}{a^{2}} + \dfrac{y^{2}}{b^{2}} = 1 cuts the positive xx and yy axes at PP and QQ respectively. The point RR divides PQPQ internally in the ratio 2:12 : 1. Given that the locus of RR is a2x2+4b2y2=λ\dfrac{a^{2}}{x^{2}} + \dfrac{4b^{2}}{y^{2}} = \lambda, find λ\lambda.
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medium
For how many values of cc does the line y=cx+cy = cx + c, c∈Rc \in \mathbb{R}, touch the curve x24+y21=1\dfrac{x^{2}}{4} + \dfrac{y^{2}}{1} = 1?
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medium
Let AA be a point on the ellipse x2+16y2=4x^{2} + 16y^{2} = 4, whose foci are S1S_1 and S2S_2. Find the maximum value of AS1⋅AS2AS_1 \cdot AS_2.
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easy
The equation x210−a+y24−a=1\dfrac{x^2}{10-a}+\dfrac{y^2}{4-a}=1 represents an ellipse if:
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easy
The eccentricity of the ellipse (x−3)2+(y−4)2=y29(x-3)^2+(y-4)^2=\dfrac{y^2}{9} is:
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easy
An ellipse has foci at (9,20)(9,20) and (49,55)(49,55) in the xyxy-plane and is tangent to the xx-axis. The length of its major axis is:
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easy
If x2f(4a)+y2f(a2−5)=1\dfrac{x^2}{f(4a)}+\dfrac{y^2}{f(a^2-5)}=1 represents an ellipse with major axis as yy-axis and ff is a decreasing function, then
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easy
If b2=a2(1−e2)b^2=a^2(1-e^2), then for any α\alpha, a,b∈Ra,b\in\mathbb{R},
a2cos⁡2α+b2sin⁡2α−2a2ecos⁡α+a2e2+a2cos⁡2α+b2sin⁡2α+2a2ecos⁡α+a2e2\sqrt{a^2\cos^2\alpha+b^2\sin^2\alpha-2a^2e\cos\alpha+a^2e^2}+\sqrt{a^2\cos^2\alpha+b^2\sin^2\alpha+2a^2e\cos\alpha+a^2e^2}
is equal to:
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easy
If an ellipse slides on the rectangular coordinate axes and foci of the ellipse are at (2,y1)(2,y_1) and (3,y2)(3,y_2), then y1y2y_1y_2 equals
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easy
The foci of the ellipse 3x2−4xy+3y2=53x^2-4xy+3y^2=5 are
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easy
The minimum value of {(r+5−4∣cos⁡θ∣)2+(r−3∣sin⁡θ∣)2}\left\{(r+5-4|\cos\theta|)^2+(r-3|\sin\theta|)^2\right\}, ∀ r,θ∈R\forall\,r,\theta\in\mathbb{R}, is:
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easy
The area of the triangle inscribed in an ellipse bears the ratio 5:3\sqrt5:3 to the area of the triangle formed by joining points on the auxiliary circle corresponding to the vertices of the first triangle. Then the eccentricity of the ellipse is:
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easy
Which one of the following is the common tangent to the ellipses x2a2+b2+y2b2=1\dfrac{x^2}{a^2+b^2}+\dfrac{y^2}{b^2}=1 and x2a2+y2a2+b2=1\dfrac{x^2}{a^2}+\dfrac{y^2}{a^2+b^2}=1?
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easy
If tan⁡θ1tan⁡θ2=−a2b2\tan\theta_1\tan\theta_2=-\dfrac{a^2}{b^2}, then the chord joining the points θ1\theta_1 and θ2\theta_2 on the ellipse x2a2+y2b2=1\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1 subtends a right angle at:
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easy
Let PP be a point on the ellipse x2a2+y2b2=1 (a>b)\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1\ (a>b) in the first quadrant, whose foci are S1S_1 and S2S_2. Then the least possible value of the circumradius of △PS1S2\triangle PS_1S_2 is:
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easy
If CFCF is the perpendicular from the centre CC of the ellipse x2a2+y2b2=1\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1 on the tangent at a point PP, and GG is the point where the normal at PP meets the major axis, then CF⋅PGCF\cdot PG is:
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easy
Tangents are drawn to the ellipse x29+y25=1\dfrac{x^2}{9}+\dfrac{y^2}{5}=1 at the ends of the latus rectum. The area of the quadrilateral so formed is:
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easy
If the ellipse x2a2−3+y2a+4=1\dfrac{x^2}{a^2-3}+\dfrac{y^2}{a+4}=1 is inscribed in a square of side length a2a\sqrt2 units, then aa is:
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easy
Let there exist at least one normal to an ellipse which touches a concentric circle, and the circle intersects the ellipse at four distinct points. Then the eccentricity of the ellipse is:
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easy
Tangents are drawn from any point on the circle x2+y2=41x^2+y^2=41 to the ellipse x225+y216=1\dfrac{x^2}{25}+\dfrac{y^2}{16}=1. The angle between the two tangents is:
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easy
The conics x2a2+y2b2=1\dfrac{x^{2}}{a^{2}} + \dfrac{y^{2}}{b^{2}} = 1 and x2A2−y2B2=1\dfrac{x^{2}}{A^{2}} - \dfrac{y^{2}}{B^{2}} = 1, where a>Aa > A and a>ba > b, have the same pair of foci S1S_1 and S2S_2, and PP is a point common to both. Find the quadratic equation whose roots are S1PS_1P and S2PS_2P.
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easy
Take the four points
(±aba2+b2, ±aba2+b2)\left(\pm\frac{ab}{\sqrt{a^{2}+b^{2}}},\ \pm\frac{ab}{\sqrt{a^{2}+b^{2}}}\right)
Which of the following is correct?
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